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Question
If x = a sin θ and y = bcos θ , write the value of`(b^2 x^2 + a^2 y^2)`
Solution
`(b^2 x^2 + a^2 y^2)`
=`b^2 (a sin theta )^2 + a^2 ( bcos theta)^2`
=`b^2 a^2 sin^2 theta + a^2 b^2 cos^2 theta`
=`a^2 b^2 ( sin^2 theta + cos ^2 theta)`
=`a^2 b^2 (1)`
=`a^2 b^2`
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