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Question
(i)` (1-cos^2 theta )cosec^2theta = 1`
Solution
LHS= `(1-cos^2 theta) cosec^2 theta`
=`sin ^2 theta cosec^2 theta (∵ cos^2 theta + sin^2 theta =1)`
=`1/(cosec^2theta) ×cosec^2theta`
=1
Hence, LHS = RHS
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