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Question
Solve the following differential equation `("d"y)/("d"x)` = x2y + y
Solution
`("d"y)/("d"x)` = x2y + y
= (x2 + 1)y
∴ `1/y "d"y` = (x2 + 1) dx
Integrating on both sides, we get
`int 1/y "d"y = int(x^2 + 1) "d"x`
∴ log |y| = `x^3/3 + x + c`
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`square`
This is the general solution.
