Advertisements
Advertisements
Question
Choose the correct alternative.
The differential equation of y = `k_1 + k_2/x` is
Options
`(d^2y)/dx^2 + 2 dy/dx = 0`
`x(d^2y)/dx^2 + 2 dy/dx = 0`
`(d^2y)/dx^2 -2 dy/dx = 0`
`x(d^2y)/dx^2 -2 dy/dx = 0`
Solution
The differential equation of `y = k_1 + k_2/x` is `x(d^2y)/dx^2 + 2 dy/dx = 0`
Explanation
`y = k_1 + k_2/x`
∴ xy = xk1 + k2
Differentiating w.r.t. x, we get
`y+x dy/dx = k_1`
Again, differentiating w.r.t. x, we get
`dy/dx + dy/dx + x (d^2y)/dx^2 = 0`
∴ `x (d^2y)/dx^2 + 2 dy/dx = 0`
APPEARS IN
RELATED QUESTIONS
Verify that y2 = 4ax is a solution of the differential equation y = x \[\frac{dy}{dx} + a\frac{dx}{dy}\]
Differential equation \[\frac{d^2 y}{d x^2} - 2\frac{dy}{dx} + y = 0, y \left( 0 \right) = 1, y' \left( 0 \right) = 2\] Function y = xex + ex
(1 + x) (1 + y2) dx + (1 + y) (1 + x2) dy = 0
Solve the following differential equation:
\[y\left( 1 - x^2 \right)\frac{dy}{dx} = x\left( 1 + y^2 \right)\]
Solve the differential equation \[\left( 1 + x^2 \right)\frac{dy}{dx} + \left( 1 + y^2 \right) = 0\], given that y = 1, when x = 0.
(x + 2y) dx − (2x − y) dy = 0
Solve the following initial value problem:-
\[\tan x\left( \frac{dy}{dx} \right) = 2x\tan x + x^2 - y; \tan x \neq 0\] given that y = 0 when \[x = \frac{\pi}{2}\]
Find the equation of the curve which passes through the point (1, 2) and the distance between the foot of the ordinate of the point of contact and the point of intersection of the tangent with x-axis is twice the abscissa of the point of contact.
Integrating factor of the differential equation cos \[x\frac{dy}{dx} + y\] sin x = 1, is
The solution of the differential equation \[\frac{dy}{dx} - \frac{y\left( x + 1 \right)}{x} = 0\] is given by
Which of the following differential equations has y = C1 ex + C2 e−x as the general solution?
Form the differential equation of the family of parabolas having vertex at origin and axis along positive y-axis.
Solve the differential equation:
`"x"("dy")/("dx")+"y"=3"x"^2-2`
A solution of a differential equation which can be obtained from the general solution by giving particular values to the arbitrary constants is called ___________ solution.
Solve the following differential equation `("d"y)/("d"x)` = x2y + y