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Find the principal solution and general solution of the following:tan θ = -13 - Mathematics

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प्रश्न

Find the principal solution and general solution of the following:
tan θ = `- 1/sqrt(3)`

योग

उत्तर

The principal value of tan θ lies in `(- pi/2, pi/2)`

Since tan θ = `- 1/sqrt(3) > 0`

The principal value of tan θ lies in the IV quadrant.

tan θ = `- 1/sqrt(3)`

= `- tan  pi/6`

tan θ = `tan ( - pi/6)`

θ = `- pi/6` is the principal solution.

The general solution of tan θ is

θ = `"n"pi - pi/6`, n ∈ Z

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.8 [पृष्ठ १३३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.8 | Q 1. (iii) | पृष्ठ १३३

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