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Prove that sin2A . tan A + cos2A . cot A + 2 sin A . cos A = tan A + cot A - Geometry Mathematics 2

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प्रश्न

Prove that

sin2A . tan A + cos2A . cot A + 2 sin A . cos A = tan A + cot A

योग

उत्तर

L.H.S = sin2A . tan A + cos2A . cot A + 2 sin A . cos A

= `sin^2"A"* (sin "A")/(cos "A")  + cos^2"A"* (cos"A")/(sin"A") + 2sin"A" *cos"A"`

= `(sin^3"A")/"cosA" + (cos^3"A")/"sinA" + 2sin"A"*cos"A"`

= `(sin^4"A" + cos^4"A" + 2sin^2"A"cos^2"A")/(sin"A"cos"A")`

= `(sin^2"A" + cos^2"A")^2/(sin"A"cos"A")` .....[∵ a2 + b2 + 2ab = (a + b)2]

= `1^2/(sin"A"cos"A")`    ......[∵ sin2A + cos2A = 1]

=  `1/(sin"A"cos"A")`  

= `(sin^2"A"+ cos^2"A")/(sin"A"cos"A")`  ......[∵ 1 = sin2A + cos2A]

= `(sin^2"A")/(sin"A"cos"A") + (cos^2"A")/(sin"A"cos"A")`

= `"sin A"/"cos A" + "cos A"/"sin A"`

= tan A + cot A

= R.H.S

∴ sin2A . tan A + cos2A . cot A + 2 sin A . cos A = tan A + cot A

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