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प्रश्न
`4sin^-1x=pi-cos^-1x`
उत्तर
`4sin^-1x=pi-cos^-1x`
⇒ `4sin^-1x=pi-(pi/2-sin^-1x)` `[becausecos^-1x=pi/2-sin^-1x]`
⇒ `4sin^-1x=pi/2+sin^-1x`
⇒ `3sin^-1x=pi/2`
⇒ `sin^-1x=pi/6`
⇒ `x=sin pi/6=1/2`
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