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Prove that: 2sin-1 35=tan-1 247 - Mathematics

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प्रश्न

Prove that:

`2sin^-1  3/5=tan^-1  24/7`

बेरीज

उत्तर

= `2sin^-1  3/5 = 2tan^-1  3/sqrt(5^2 - 3^2)`    ...`[sin^-1  "p"/"h" = tan^-1  "p"/sqrt("h"^2 - "p"^2)]`

= `2tan^-1  3/4`

= `tan^-1  (2 xx 3/4)/(1 - (3/4)^2)`    ...`[2tan^-1 = tan^-1  (2x)/(1 - x^2)]`

= `tan^-1  (3/2)/(7/16)`

`= tan^-1  24/7`

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.14 [पृष्ठ ११५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.14 | Q 2.01 | पृष्ठ ११५

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