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प्रश्न
Evaluate:
`sin(tan^-1x+tan^-1 1/x)` for x > 0
उत्तर
`sin(tan^-1x+tan^-1 1/x)`
`=sin(tan^-1x+cot^-1x)` `[thereforetan^-1x=cot^-1 1/x]`
`=sin(pi/2)` `[thereforetan^-1x=cot^-1x=pi/2]`
= 1
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