मराठी

Write the Value of Cos−1 (Cos 1540°). - Mathematics

Advertisements
Advertisements

प्रश्न

Write the value of cos−1 (cos 1540°).

उत्तर

We know that 

\[\cos^{- 1} \left( cosx \right) = x\]

Now,

\[\cos^{- 1} \left( \cos {1540}^\circ \right) = \cos^{- 1} \left\{ \cos\left( 1440 + {100}^\circ \right) \right\}\]
\[ = \cos^{- 1} \left\{ \cos\left( {100}^\circ \right) \right\} \left[ \because \cos\left( 4\pi + {100}^\circ \right) = \cos{100}^\circ \right]\]
\[ = {100}^\circ\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 13 | पृष्ठ ११७

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

​Find the principal values of the following:
`cos^-1(-sqrt3/2)`


`sin^-1{(sin - (17pi)/8)}`


`sin^-1(sin3)`


`sin^-1(sin12)`


Evaluate the following:

`cos^-1{cos  ((4pi)/3)}`


Write the following in the simplest form:

`cot^-1  a/sqrt(x^2-a^2),|  x  | > a`


Evaluate the following:

`tan(cos^-1  8/17)`


Prove the following result

`tan(cos^-1  4/5+tan^-1  2/3)=17/6`


Prove the following result

`sin(cos^-1  3/5+sin^-1  5/13)=63/65`


`sin(sin^-1  1/5+cos^-1x)=1`


Solve the following equation for x:

tan−1(x + 2) + tan−1(x − 2) = tan−1 `(8/79)`, x > 0


Solve the following equation for x:

`tan^-1  x/2+tan^-1  x/3=pi/4, 0<x<sqrt6`


Sum the following series:

`tan^-1  1/3+tan^-1  2/9+tan^-1  4/33+...+tan^-1  (2^(n-1))/(1+2^(2n-1))`


`tan^-1  1/4+tan^-1  2/9=1/2cos^-1  3/2=1/2sin^-1(4/5)`


Solve the following equation for x:

`tan^-1  1/4+2tan^-1  1/5+tan^-1  1/6+tan^-1  1/x=pi/4`


Prove that `2tan^-1(sqrt((a-b)/(a+b))tan  theta/2)=cos^-1((a costheta+b)/(a+b costheta))`


Write the value of `sin^-1((-sqrt3)/2)+cos^-1((-1)/2)`


If x > 1, then write the value of sin−1 `((2x)/(1+x^2))` in terms of tan−1 x.


What is the value of cos−1 `(cos  (2x)/3)+sin^-1(sin  (2x)/3)?`


If tan−1 x + tan−1 y = `pi/4`,  then write the value of x + y + xy.


Write the value of cos−1 (cos 6).


Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]


Write the value of \[\tan^{- 1} \frac{a}{b} - \tan^{- 1} \left( \frac{a - b}{a + b} \right)\]


Write the value of \[\sin^{- 1} \left( \frac{1}{3} \right) - \cos^{- 1} \left( - \frac{1}{3} \right)\]


Write the principal value of `sin^-1(-1/2)`


Write the principal value of `tan^-1sqrt3+cot^-1sqrt3`


Write the principal value of \[\cos^{- 1} \left( \cos680^\circ  \right)\]


If \[\cos\left( \sin^{- 1} \frac{2}{5} + \cos^{- 1} x \right) = 0\], find the value of x.

 

If \[\tan^{- 1} \left( \frac{\sqrt{1 + x^2} - \sqrt{1 - x^2}}{\sqrt{1 + x^2} + \sqrt{1 - x^2}} \right)\]  = α, then x2 =




The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]


Let f (x) = `e^(cos^-1){sin(x+pi/3}.`
Then, f (8π/9) = 


If tan−1 3 + tan−1 x = tan−1 8, then x =


The value of \[\sin^{- 1} \left( \cos\frac{33\pi}{5} \right)\] is 

 


The value of  \[\sin\left( 2\left( \tan^{- 1} 0 . 75 \right) \right)\] is equal to

 


The value of \[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right)\]

 


Find the real solutions of the equation
`tan^-1 sqrt(x(x + 1)) + sin^-1 sqrt(x^2 + x + 1) = pi/2`


The value of sin `["cos"^-1 (7/25)]` is ____________.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×