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प्रश्न
`sin^-1(sin12)`
उत्तर
We know
`sin(sin^-1theta)=theta if - pi/2<=theta<=pi/2`
We have
= `sin^-1sin36°`
= `- sin^-1sin(4pi-12)`
= `-(4pi-12)`
= `-4pi+12`
= `12-4pi`
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