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प्रश्न
`tan^-1 2/3=1/2tan^-1 12/5`
उत्तर
LHS = `tan^-1 2/3`
`=1/2tan^-1{(2xx2/3)/(1-(2/3)^2)}` `[becausetan^-1x=1/2tan^-1{(2x)/(1-x^2)}]`
`=1/2tan^-1{(4/3)/(5/9)}`
`=1/2tan^-1 12/5=`RHS
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