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प्रश्न
`5/(sin^2theta) - 5cot^2theta`, complete the activity given below.
Activity:
`5/(sin^2theta) - 5cot^2theta`
= `square (1/(sin^2theta) - cot^2theta)`
= `5(square - cot^2theta) ......[1/(sin^2theta) = square]`
= 5(1)
= `square`
उत्तर
`5/(sin^2theta) - 5cot^2theta`
= `5 (1/(sin^2theta) - cot^2theta)`
= `5("cosec"^2theta - cot^2theta) ......[1/(sin^2theta) = "cosec"^2theta]`
= 5(1)
= 5.
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