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प्रश्न
If `secθ = 25/7 ` then find tanθ.
उत्तर
`1 + tan^2θ = sec^2θ`
`1 + tan^2θ =(25/7)^2`
`∴ tan^2θ =625/49- 1`
`∴ tan^2θ =(625-49)/49`
`∴ tan^2θ =576/49`
`∴ tanθ =24/7`
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संबंधित प्रश्न
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If cot θ = `40/9`, find the values of cosec θ and sinθ,
We have, 1 + cot2θ = cosec2θ
1 + `square` = cosec2θ
1 + `square` = cosec2θ
`(square + square)/square` = cosec2θ
`square/square` = cosec2θ ......[Taking root on the both side]
cosec θ = `41/9`
and sin θ = `1/("cosec" θ)`
sin θ = `1/square`
∴ sin θ = `9/41`
The value is cosec θ = `41/9`, and sin θ = `9/41`
