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What is the Principal Value of Sin − 1 ( − √ 3 /2 ) ? - Mathematics

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प्रश्न

What is the principal value of `sin^-1(-sqrt3/2)?`

उत्तर

Let `y=sin^-1(-sqrt3/2)`
Then,
\[\sin{y} = - \frac{\sqrt{3}}{2} = \sin\left( - \frac{\pi}{3} \right)\]
\[y = - \frac{\pi}{3} \in \left[ - \frac{\pi}{2}, \frac{\pi}{2} \right]\]
Here
\[\left[ - \frac{\pi}{2}, \frac{\pi}{2} \right]\]  is the range of the principal value branch of inverse sine function.

∴ `sin^-1(-sqrt3/2)=-pi/3`

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११८]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 38 | पृष्ठ ११८

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