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Question
ABC is an isosceles right-angled triangle. Assuming of AB = BC = x, find the value of each of the following trigonometric ratios: sin 45°
Solution
Given that AB = BC = x
∴ AC = `sqrt(AB^2+BC^2) = sqrt(x^2 + x^2) = xsqrt2`
sin 45° = `"AB"/"AC" = x/(xsqrt2) = 1/sqrt2`
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