English

Evaluate the Following: `Cosec^-1(Cosec (11pi)/6)` - Mathematics

Advertisements
Advertisements

Question

Evaluate the following:

`cosec^-1(cosec  (11pi)/6)`

Solution

We know that

cosec-1 (cosec θ) = θ,    [-π/2,0) ∪ (0,π/2]

`cosec^-1(cosec  (11pi)/6)=cosec^-1[cosec(2pi-pi/6)]`

`=cosec^-1(cosec - pi/6)`

`=-pi/6`

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.07 [Page 42]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.07 | Q 5.4 | Page 42

RELATED QUESTIONS

 

Prove that :

`2 tan^-1 (sqrt((a-b)/(a+b))tan(x/2))=cos^-1 ((a cos x+b)/(a+b cosx))`

 

Prove that

`tan^(-1) [(sqrt(1+x)-sqrt(1-x))/(sqrt(1+x)+sqrt(1-x))]=pi/4-1/2 cos^(-1)x,-1/sqrt2<=x<=1`


 

If `tan^(-1)((x-2)/(x-4)) +tan^(-1)((x+2)/(x+4))=pi/4` ,find the value of x

 

If `(sin^-1x)^2 + (sin^-1y)^2+(sin^-1z)^2=3/4pi^2,`  find the value of x2 + y2 + z2 


`sin^-1(sin  (5pi)/6)`


`sin^-1(sin  (13pi)/7)`


`sin^-1(sin4)`


`sin^-1(sin2)`


Evaluate the following:

`cos^-1{cos  ((4pi)/3)}`


Evaluate the following:

`tan^-1(tan  (9pi)/4)`


Evaluate the following:

`sec^-1(sec  pi/3)`


Evaluate the following:

`\text(cosec)^-1(\text{cosec}  pi/4)`


Evaluate the following:

`cot^-1{cot (-(8pi)/3)}`


Evaluate the following:

`sin(tan^-1  24/7)`


Prove the following result-

`tan^-1  63/16 = sin^-1  5/13 + cos^-1  3/5`


Evaluate:

`cos(tan^-1  3/4)`


If `cot(cos^-1  3/5+sin^-1x)=0`, find the values of x.


Solve the following equation for x:

tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x


Solve the following equation for x:

`tan^-1((x-2)/(x-4))+tan^-1((x+2)/(x+4))=pi/4`


`sin^-1  63/65=sin^-1  5/13+cos^-1  3/5`


Evaluate the following:

`sin(1/2cos^-1  4/5)`


`tan^-1  1/7+2tan^-1  1/3=pi/4`


`sin^-1  4/5+2tan^-1  1/3=pi/2`


`2sin^-1  3/5-tan^-1  17/31=pi/4`


`2tan^-1  1/5+tan^-1  1/8=tan^-1  4/7`


`2tan^-1  3/4-tan^-1  17/31=pi/4`


`2tan^-1(1/2)+tan^-1(1/7)=tan^-1(31/17)`


Solve the following equation for x:

`tan^-1  1/4+2tan^-1  1/5+tan^-1  1/6+tan^-1  1/x=pi/4`


For any a, b, x, y > 0, prove that:

`2/3tan^-1((3ab^2-a^3)/(b^3-3a^2b))+2/3tan^-1((3xy^2-x^3)/(y^3-3x^2y))=tan^-1  (2alphabeta)/(alpha^2-beta^2)`

`where  alpha =-ax+by, beta=bx+ay`


If `sin^-1x+sin^-1y+sin^-1z=(3pi)/2,`  then write the value of x + y + z.


What is the principal value of `sin^-1(-sqrt3/2)?`


Write the principal value of `tan^-1sqrt3+cot^-1sqrt3`


Write the value of  \[\tan^{- 1} \left( \frac{1}{x} \right)\]  for x < 0 in terms of `cot^-1x`


Write the value of  `cot^-1(-x)`  for all `x in R` in terms of `cot^-1(x)`


If \[\cos\left( \sin^{- 1} \frac{2}{5} + \cos^{- 1} x \right) = 0\], find the value of x.

 

If \[\tan^{- 1} \left( \frac{\sqrt{1 + x^2} - \sqrt{1 - x^2}}{\sqrt{1 + x^2} + \sqrt{1 - x^2}} \right)\]  = α, then x2 =




2 tan−1 {cosec (tan−1 x) − tan (cot1 x)} is equal to


If sin−1 − cos−1 x = `pi/6` , then x = 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×