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Question
If sec2 θ (1 + sin θ) (1 − sin θ) = k, then find the value of k.
Solution
Given:
`sec^2θ {(1+sinθ) (1-sin θ)}=k`
⇒ `sec^2θ {(1+sinθ) (1-sin θ)}=k`
⇒` Sec^2θ {1+sinθ}=K`
⇒ `sec^2θ cos^2θ=k`
⇒` 1/cos^2θ xx cos ^2 θ=k`
⇒ `1=k`
⇒` k=1`
Hence, the value of k is 1.
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