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Question
In ∆ABC, cos C = `12/13` and BC = 24, then AC = ?
Solution
cos C = `12/13` .....(i) [Given]
In ∆ABC,
Let ∠ABC = 90°
∴ cos C = `"BC"/"AC"` .....(ii) [By definition]
∴ `"BC"/"AC" = 12/13` ......[From (i) and (ii)]
∴ `24/"AC" = 12/13`
∴ `(24 xx 13)/12` = AC
∴ `312/12` = AC
∴ AC = 26 units
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