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Question
Integrating factor of the differential equation `("d"y)/("d"x) + y tanx - secx` = 0 is ______.
Options
cosx
secx
ecosx
esecx
Solution
Integrating factor of the differential equation `("d"y)/("d"x) + y tanx - secx` = 0 is secx.
Explanation:
Given differential equation is `("d"y)/("d"x) + y tanx - secx` = 0
⇒ `("d"y)/("d"x) + ytanx` = secx
Here, P = tanx and Q = secx
∴ I.F. = `"e"^(intPdx)`
= `"e"^(inttanx "d"x)`
= `"e"^(log secx)`
= secx
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