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Question
The range of f(x) = cos [x], for π/2 < x < π/2 is
Options
(a) {−1, 1, 0}
(b) {cos 1, cos 2, 1}
(c) {cos 1, −cos 1, 1}
(d) [−1, 1]
Solution
(b) {cos 1, cos 2, 1}
Since, f(x) = cos [x], where \[\frac{- \pi}{2} < x < \frac{\pi}{2}\]
\[- \frac{\pi}{2} < x < \frac{\pi}{2}\]
\[ \Rightarrow - 1 . 57 < x < 1 . 57\]
\[ \Rightarrow [x] \in { - 1, 0, 1, 2}\]
\[\text{ Thus } , \cos [x] = {\cos ( - 1), \cos 0, \cos1, \cos 2 }\]
\[\text{ Range of } f(x) = {\cos 1, 1, \cos 2}\]
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