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The sum of first three terms of a G.P. is 3910 and their product is 1. Find the common ratio and the terms. - Mathematics

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Question

The sum of first three terms of a G.P. is  `39/10` and their product is 1. Find the common ratio and the terms.

Sum

Solution

Suppose the three terms of the geometric progression are `"a"/"r"`, a and ar.

Sum `"a"/"r" + "a" + "ar" = 39/10` ........(i)

And product = `"a"/"r" xx "a" xx "ar" = "a"^3 = 1`

or a = 1 ..........(ii)

By keeping a = 1 in equation (i)

`1/"r" + 1 + "r" = 39/10`

on multiplying by 10r

= 10 + 10r + 10r2 = 39r

= 10r2 − 29r + 10 =

= 10r2 - 25r - 4r + 10 = 0

= 5r (2r - 5) -2 (2r- 5) = 0

= (5r - 2) (2r - 5) = 0

r = `5/2` or `2/5`

a = 1

`1/"r" = 5/2, "r" = 2/5`

∴ Terms of geometric progression = `5/2, 1, 2/5` or `2/5, 1, 5/2`

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Chapter 9: Sequences and Series - Exercise 9.3 [Page 192]

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NCERT Mathematics [English] Class 11
Chapter 9 Sequences and Series
Exercise 9.3 | Q 12 | Page 192

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