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प्रश्न
`1+(tan^2 theta)/((1+ sec theta))= sec theta`
उत्तर
LHS = 1+`(tan^2 theta)/((1+ sec theta))`
=` 1+ ((sec^2 theta-1))/((sec theta + 1))`
=`1+((sec theta +1)(sec theta-1))/((sec theta +1))`
=`1+ (sec theta-1)`
=`sec theta`
= RHS
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