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Find the 4th Term from the End of the G.P. 2 27 , 2 9 , 2 3 , . . . , 162 - Mathematics

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प्रश्न

Find the 4th term from the end of the G.P.

\[\frac{2}{27}, \frac{2}{9}, \frac{2}{3}, . . . , 162\]

उत्तर

\[\text { Here, first term, } a = \frac{2}{27}\]

\[\text { Common ratio}, r = \frac{a_2}{a_1} = \frac{\frac{2}{9}}{\frac{2}{27}} = 3 \]

\[\text { Last term, } l = 162\]

\[\text { After reversing the given G . P . , we get another G . P . whose first term is l and common ratio is } \frac{1}{r} . \]

\[ \therefore 4th \text { term from the end } = l \left( \frac{1}{r} \right)^{4 - 1} = (162) \left( \frac{1}{3} \right)^3 = 6\]

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पाठ 20: Geometric Progression - Exercise 20.1 [पृष्ठ १०]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 20 Geometric Progression
Exercise 20.1 | Q 4 | पृष्ठ १०

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