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प्रश्न
Integrate the functions:
`(1+ log x)^2/x`
उत्तर
Let `I = int (1 + log x)^2/x dx`
Put 1 + log x = t
`1/x dt = dt`
Hence, `I = int t^2` dt
`= t^3/3 + C`
`= 1/3 (1 + log x)^3 + C`
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