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प्रश्न
Write a value of
उत्तर
Let I = ∫ x2 sin x3 dx
⇒ 3x2 dx = dt
\[\Rightarrow x^2 \text{ dx }= \frac{dt}{3}\]
\[ \therefore I = \frac{1}{3}\int \text{ sin t dt}\]
\[ = \frac{1}{3}\left[ - \cos\text{ t }\right] + C\]
\[ = - \frac{1}{3}\cos \text{ x}^3 + C \left( \because t = x^3 \right)\]
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