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प्रश्न
Prove that:
उत्तर
\[LHS = 2\left( \sin \frac{5\pi}{12} \right) \left( \cos \frac{\pi}{12} \right)\]
\[ = \sin \left( \frac{5\pi}{12} + \frac{\pi}{12} \right) + \sin \left( \frac{5\pi}{12} - \frac{\pi}{12} \right) \left[ \because 2 \sin A \cos B = \sin (A + B) + \sin (A - B) \right]\]
\[ = \sin \frac{\pi}{2} + \sin \frac{\pi}{3}\]
\[ = 1 + \frac{\sqrt{3}}{2}\]
\[ = \frac{2 + \sqrt{3}}{2}\]
\[RHS = \frac{2 + \sqrt{3}}{2}\]
Hence, LHS = RHS
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