मराठी

Write the Value of the Expression 1 − 4 Sin 10 ∘ Sin 70 ∘ 2 Sin 10 ∘ - Mathematics

Advertisements
Advertisements

प्रश्न

Write the value of the expression \[\frac{1 - 4 \sin 10^\circ \sin 70^\circ}{2 \sin 10^\circ}\]

बेरीज

उत्तर

\[\frac{1 - 4\sin10^\circ \sin70^\circ}{2\sin10^\circ}\]
\[ = \frac{1 - 2\left[ 2\sin10^\circ \sin70^\circ \right]}{2\sin10^\circ}\]
\[ = \frac{1 - 2\left[ \cos\left( 10^\circ - 70^\circ \right) - \cos\left( 10^\circ + 70^\circ \right) \right]}{2\sin10^\circ}\]
\[ = \frac{1 - 2\left[ \cos\left( - 60^\circ \right) - \cos80^\circ \right]}{2\sin10^\circ}\]
\[ = \frac{1 - 2\left[ \cos60^\circ - \cos80^\circ \right]}{2\sin10^\circ}\]
\[ = \frac{1 - 2\left[ \frac{1}{2} - \cos\left( 90^\circ - 10^\circ \right) \right]}{2\sin10^\circ}\]
\[ = \frac{1 - 2 \times \frac{1}{2} + 2\cos\left( 90^\circ - 10^\circ \right)}{2\sin10^\circ}\]
\[ = \frac{2\sin10^\circ}{2\sin10^\circ}\]
\[ = 1\]

shaalaa.com
Transformation Formulae
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Transformation formulae - Exercise 8.3 [पृष्ठ २०]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.3 | Q 5 | पृष्ठ २०

संबंधित प्रश्‍न

Prove that: 

\[2\sin\frac{5\pi}{12}\cos\frac{\pi}{12} = \frac{\sqrt{3} + 2}{2}\]

Prove that:
cos 40° cos 80° cos 160° = \[- \frac{1}{8}\]

 


Express each of the following as the product of sines and cosines:
sin 12x + sin 4x


Express each of the following as the product of sines and cosines:
 cos 12x + cos 8x


Prove that:
 sin 23° + sin 37° = cos 7°


Prove that:
 cos 80° + cos 40° − cos 20° = 0


Prove that:
\[\sin\frac{5\pi}{18} - \cos\frac{4\pi}{9} = \sqrt{3} \sin\frac{\pi}{9}\]


Prove that:

sin 51° + cos 81° = cos 21°

Prove that:
 `sin A + sin 2A + sin 4A + sin 5A = 4 cos (A/2) cos((3A)/2)sin3A`


Prove that:
sin 3A + sin 2A − sin A = 4 sin A cos \[\frac{A}{2}\] \[\frac{3A}{2}\]

 


Prove that:

cos 20° cos 100° + cos 100° cos 140° − 140° cos 200° = −\[\frac{3}{4}\]

 


Prove that:

\[\frac{\sin A + \sin 3A + \sin 5A}{\cos A + \cos 3A + \cos 5A} = \tan 3A\]

 


Prove that:

\[\frac{\cos 4A + \cos 3A + \cos 2A}{\sin 4A + \sin 3A + \sin 2A} = \cot 3A\]

 


Prove that:

\[\frac{\sin 3A + \sin 5A + \sin 7A + \sin 9A}{\cos 3A + \cos 5A + \cos 7A + \cos 9A} = \tan 6A\]

Prove that:

\[\frac{\sin 5A - \sin 7A + \sin 8A - \sin 4A}{\cos 4A + \cos 7A - \cos 5A - \cos 8A} = \cot 6A\]

Prove that:

\[\frac{\sin 11A \sin A + \sin 7A \sin 3A}{\cos 11A \sin A + \cos 7A \sin 3A} = \tan 8A\]

Prove that:

\[\frac{\sin 3A \cos 4A - \sin A \cos 2A}{\sin 4A \sin A + \cos 6A \cos A} = \tan 2A\]

\[\text{ If } \cos A + \cos B = \frac{1}{2}\text{ and }\sin A + \sin B = \frac{1}{4},\text{ prove that }\tan\left( \frac{A + B}{2} \right) = \frac{1}{2} .\]

 


If cosec A + sec A = cosec B + sec B, prove that tan A tan B = \[\cot\frac{A + B}{2}\].


If cos (A + B) sin (C − D) = cos (A − B) sin (C + D), prove that tan A tan B tan C + tan D = 0.

 

If (cos α + cos β)2 + (sin α + sin β)2 = \[\lambda \cos^2 \left( \frac{\alpha - \beta}{2} \right)\], write the value of λ. 


Write the value of sin \[\frac{\pi}{12}\] sin \[\frac{5\pi}{12}\].


Write the value of \[\sin\frac{\pi}{15}\sin\frac{4\pi}{15}\sin\frac{3\pi}{10}\]


sin 163° cos 347° + sin 73° sin 167° =


cos 35° + cos 85° + cos 155° =


The value of sin 50° − sin 70° + sin 10° is equal to


If cos A = m cos B, then \[\cot\frac{A + B}{2} \cot\frac{B - A}{2}\]=

 

Express the following as the sum or difference of sine or cosine:

`sin  "A"/8  sin  (3"A")/8`


Express the following as the sum or difference of sine or cosine:

cos(60° + A) sin(120° + A)


Prove that:

tan 20° tan 40° tan 80° = `sqrt3`.


Prove that:

`(cos 7"A" +cos 5"A")/(sin 7"A" −sin 5"A")` = cot A


Prove that cos 20° cos 40° cos 60° cos 80° = `3/16`.


If sin(y + z – x), sin(z + x – y), sin(x + y – z) are in A.P, then prove that tan x, tan y and tan z are in A.P.


If tan θ = `1/sqrt5` and θ lies in the first quadrant then cos θ is:


If secx cos5x + 1 = 0, where 0 < x ≤ `pi/2`, then find the value of x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×