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Question
Evaluate: `int1/(xlogxlog(logx))dx`
Solution
`Let I= int1/(x.logxlog(logx))dx`
Put log (log x) = t
Differentiating w.r.t. x, we get
`1/logx.1/xdx=dt`
`I=int1/tdt=log|t|+c`
`I=log|log(logx)|+c`
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