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Question
Fill in the blank : `int_0^1 dx/(2x + 5)` = _______
Solution
Let I = `int_0^1 dx/(2x + 5)`
Put 2x + 5 = t
∴ 2dx = dt
∴ dx = `"dt"/(2)`
When x = 0, t = 2(0) + 5 = 5
When x = 1, t = 2(1) + 5 = 7
∴ I = `(1)/(2) int_5^7 "dt"/"t"`
= `(1)/(2)[log|"t"|]_5^7`
= `(1)/(2)(log 7 - log 5)`
= `(1)/(2)log(7/5)`.
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