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Question
If x sin (90° − θ) cot (90° − θ) = cos (90° − θ), then x =
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Solution
We have: x sin(90°-θ) cot (90°-θ)=cos (90°-θ)
Here we have to find the value of x
We have: ` x sin (90°-θ)= cos θ, cos (90°-θ)= sin θ , `
`cot (90°-θ)= tan θ,`
⇒ `x sin (90°-θ) cot (90°-θ)= cos (90°-θ)`
⇒` x cos θ tan θ=sin θ`
⇒ `x cos θ xx sin θ/cos θ=sinθ`
⇒ `x=1`
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