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Question
Prove that `(sintheta + tantheta)/cos theta` = tan θ(1 + sec θ)
Solution
L.H.S = `(sintheta + tantheta)/cos theta`
= `sintheta/costheta + tantheta/costheta`
= tan θ + tan θ sec θ
= tan θ(1 + sec θ)
= R.H.S
∴ `(sintheta + tantheta)/cos theta` = tan θ(1 + sec θ)
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