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प्रश्न
`1+ (cot^2 theta)/((1+ cosec theta))= cosec theta`
उत्तर
LHS =` 1+(cot^2 theta)/((1+ cosectheta))`
=`1+((cosec^2 theta-1))/((cosectheta++1)) (∵ cosec^2 theta - cot^2 theta =1)`
=`1+((cosectheta+1)(cosec theta-1))/((cosec theta +1))`
=`1+ (cosec theta -1)`
=` cosec theta`
=RHS
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