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प्रश्न
Evaluate the following:
`sin(tan^-1 24/7)`
उत्तर
`sin(tan^-1 24/7)=sin(sin^-1 (24/7)/sqrt(1+(24/7)^2))` `[thereforetan^-1x=x/sqrt(1+x^2)]`
`=sin(sin^-1 (24/7)/sqrt(1+576/49))`
`=sin(sin^-1 (24/7)/sqrt(625/49))`
`=sin(sin^-1 (24/7)/(25/7))`
`=24/25`
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