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If X > 1, Then 2 Tan − 1 X + Sin − 1 ( 2 X 1 + X 2 ) is Equal to (A) 4 Tan − 1 X (B) 0 (C) π 2 (D) π - Mathematics

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प्रश्न

If > 1, then \[2 \tan^{- 1} x + \sin^{- 1} \left( \frac{2x}{1 + x^2} \right)\] is equal to

 

विकल्प

  • `4tan^-1x`

  • 0

  • `pi/2`

     

  •  π

MCQ

उत्तर

\[2 \tan^{- 1} x + \sin^{- 1} \left( \frac{2x}{1 + x^2} \right) = 2 \tan^{- 1} x + 2 \tan^{- 1} x \left[ \because \sin^{- 1} \left( \frac{2x}{1 + x^2} \right) = 2 \tan^{- 1} x \right]\]
\[ = 4 \tan^{- 1} x\]

Hence, the correct answer is option (a)

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.16 [पृष्ठ १२२]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 33 | पृष्ठ १२२

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