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प्रश्न
`(sec^2 theta -1)(cosec^2 theta - 1)=1`
उत्तर
LHS = `(sec^2 theta -1)(cosec^2 theta-1)`
=`tan^2 theta xx cot^2 theta ( ∵ sec^2 theta - tan^2 theta = 1 and cosec^2 theta - cot^2 theta =1)`
=` tan^2 theta xx1/(cos^2theta)`
=1
=RHS
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संबंधित प्रश्न
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Solution:
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∴ 1 + tan2 θ = `(25/7)^square`
∴ tan2 θ = `625/49 - square`
= `(625 - 49)/49`
= `square/49`
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