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Show that cos 38° cos 52° − sin 38° sin 52° = 0 - Mathematics

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प्रश्न

Show that cos 38° cos 52° − sin 38° sin 52° = 0

उत्तर

cos 38° cos 52° − sin 38° sin 52°

= cos (90° − 52°) cos (90°−38°) − sin 38° sin 52°

= sin 52° sin 38° − sin 38° sin 52°

= 0

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अध्याय 8: Introduction to Trigonometry - Exercise 8.3 [पृष्ठ १८९]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 8 Introduction to Trigonometry
Exercise 8.3 | Q 2.2 | पृष्ठ १८९

वीडियो ट्यूटोरियलVIEW ALL [2]

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