हिंदी

Solve the equation x2-2x+32=0 - Mathematics

Advertisements
Advertisements

प्रश्न

Solve the equation   `x^2 -2x + 3/2 = 0`  

योग

उत्तर

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Complex Numbers and Quadratic Equations - Miscellaneous Exercise [पृष्ठ ११२]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 5 Complex Numbers and Quadratic Equations
Miscellaneous Exercise | Q 7 | पृष्ठ ११२

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Solve the equation 2x2 + x + 1 = 0


Solve the equation x2 + 3x + 9 = 0


Solve the equation x2 – x + 2 = 0


Solve the equation  `x^2 + x/sqrt2 + 1 = 0`


x2 + 2x + 5 = 0


4x2 − 12x + 25 = 0


x2 + x + 1 = 0


\[21 x^2 + 9x + 1 = 0\]


\[17 x^2 - 8x + 1 = 0\]


\[21 x^2 - 28x + 10 = 0\]


\[8 x^2 - 9x + 3 = 0\]


\[13 x^2 + 7x + 1 = 0\]


\[2 x^2 + x + 1 = 0\]


\[\sqrt{3} x^2 - \sqrt{2}x + 3\sqrt{3} = 0\]


\[x^2 + \frac{x}{\sqrt{2}} + 1 = 0\]


\[x^2 - 2x + \frac{3}{2} = 0\]


\[3 x^2 - 4x + \frac{20}{3} = 0\]


Solve the following quadratic equation:

\[x^2 - \left( 3\sqrt{2} - 2i \right) x - \sqrt{2} i = 0\]


Solve the following quadratic equation:

\[x^2 - \left( \sqrt{2} + i \right) x + \sqrt{2}i = 0\]


Solve the following quadratic equation:

\[2 x^2 - \left( 3 + 7i \right) x + \left( 9i - 3 \right) = 0\]


Write the number of real roots of the equation \[(x - 1 )^2 + (x - 2 )^2 + (x - 3 )^2 = 0\].


If a and b are roots of the equation \[x^2 - px + q = 0\], than write the value of \[\frac{1}{a} + \frac{1}{b}\].


If the difference between the roots of the equation \[x^2 + ax + 8 = 0\] is 2, write the values of a.


If a and b are roots of the equation \[x^2 - x + 1 = 0\],  then write the value of a2 + b2.


If α, β are roots of the equation \[x^2 - a(x + 1) - c = 0\] then write the value of (1 + α) (1 + β).


The complete set of values of k, for which the quadratic equation  \[x^2 - kx + k + 2 = 0\] has equal roots, consists of


The values of x satisfying log3 \[( x^2 + 4x + 12) = 2\] are


If α, β are the roots of the equation \[a x^2 + bx + c = 0, \text { then } \frac{1}{a\alpha + b} + \frac{1}{a\beta + b} =\]


The number of real solutions of \[\left| 2x - x^2 - 3 \right| = 1\] is


If the equations \[x^2 + 2x + 3\lambda = 0 \text { and } 2 x^2 + 3x + 5\lambda = 0\]  have a non-zero common roots, then λ =


The number of roots of the equation \[\frac{(x + 2)(x - 5)}{(x - 3)(x + 6)} = \frac{x - 2}{x + 4}\] is 


If the difference of the roots of \[x^2 - px + q = 0\]  is unity, then

 

If α, β are the roots of the equation \[x^2 - p(x + 1) - c = 0, \text { then } (\alpha + 1)(\beta + 1) =\]


The least value of which makes the roots of the equation  \[x^2 + 5x + k = 0\]  imaginary is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×