हिंदी

Write the Value of Cos − 1 ( Cos 14 π 3 ) - Mathematics

Advertisements
Advertisements

प्रश्न

Write the value of \[\cos^{- 1} \left( \cos\frac{14\pi}{3} \right)\]

उत्तर

\[\cos^{- 1} \left( \cos\frac{14\pi}{3} \right) = \cos^{- 1} \left[ \cos\left( 4\pi + \frac{2\pi}{3} \right) \right]\]
\[ = \cos^{- 1} \left( \cos\frac{2\pi}{3} \right)\]
\[ = \frac{2\pi}{3}\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११८]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 48 | पृष्ठ ११८

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

If `cos^-1( x/a) +cos^-1 (y/b)=alpha` , prove that `x^2/a^2-2(xy)/(ab) cos alpha +y^2/b^2=sin^2alpha`


Solve for x:

`2tan^(-1)(cosx)=tan^(-1)(2"cosec" x)`


If sin [cot−1 (x+1)] = cos(tan1x), then find x.


​Find the principal values of the following:
`cos^-1(-sqrt3/2)`


Evaluate the following:

`cos^-1(cos4)`


Evaluate the following:

`cot^-1{cot  ((21pi)/4)}`


Write the following in the simplest form:

`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`


Evaluate the following:

`sin(sin^-1  7/25)`

 


Evaluate the following:

`sec(sin^-1  12/13)`


Evaluate:

`cosec{cot^-1(-12/5)}`


Evaluate: 

`cot(sin^-1  3/4+sec^-1  4/3)`


If `cos^-1x + cos^-1y =pi/4,`  find the value of `sin^-1x+sin^-1y`


`sin^-1x=pi/6+cos^-1x`


Solve the following equation for x:

tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x


Solve the following equation for x:

tan−1`((1-x)/(1+x))-1/2` tan−1x = 0, where x > 0


Solve the following:

`sin^-1x+sin^-1  2x=pi/3`


If `cos^-1  x/2+cos^-1  y/3=alpha,` then prove that  `9x^2-12xy cosa+4y^2=36sin^2a.`


Prove that:

`2sin^-1  3/5=tan^-1  24/7`


`2tan^-1  3/4-tan^-1  17/31=pi/4`


`4tan^-1  1/5-tan^-1  1/239=pi/4`


Prove that

`tan^-1((1-x^2)/(2x))+cot^-1((1-x^2)/(2x))=pi/2`


If `sin^-1  (2a)/(1+a^2)+sin^-1  (2b)/(1+b^2)=2tan^-1x,` Prove that  `x=(a+b)/(1-ab).`


If x < 0, then write the value of cos−1 `((1-x^2)/(1+x^2))` in terms of tan−1 x.


Write the value of tan1x + tan−1 `(1/x)`for x > 0.


Write the value of

\[\cos^{- 1} \left( \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\].


Write the principal value of \[\cos^{- 1} \left( \cos\frac{2\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{2\pi}{3} \right)\]


Wnte the value of\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right), \text{ when } x = - \frac{1}{\sqrt{3}}\]


If  \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]


sin\[\left[ \cot^{- 1} \left\{ \tan\left( \cos^{- 1} x \right) \right\} \right]\]  is equal to

 

 

\[\text{ If }\cos^{- 1} \frac{x}{3} + \cos^{- 1} \frac{y}{2} = \frac{\theta}{2}, \text{ then }4 x^2 - 12xy \cos\frac{\theta}{2} + 9 y^2 =\]


If \[\cos^{- 1} x > \sin^{- 1} x\], then


In a ∆ ABC, if C is a right angle, then
\[\tan^{- 1} \left( \frac{a}{b + c} \right) + \tan^{- 1} \left( \frac{b}{c + a} \right) =\]

 

 


If tan−1 (cot θ) = 2 θ, then θ =

 


If \[\sin^{- 1} \left( \frac{2a}{1 - a^2} \right) + \cos^{- 1} \left( \frac{1 - a^2}{1 + a^2} \right) = \tan^{- 1} \left( \frac{2x}{1 - x^2} \right),\text{ where }a, x \in \left( 0, 1 \right)\] , then, the value of x is

 


The value of sin `["cos"^-1 (7/25)]` is ____________.


The value of tan `("cos"^-1  4/5 + "tan"^-1  2/3) =`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×