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Find the Value of 2 Sec − 1 2 + Sin − 1 ( 1 2 ) - Mathematics

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प्रश्न

Find the value of \[2 \sec^{- 1} 2 + \sin^{- 1} \left( \frac{1}{2} \right)\]

उत्तर

\[2 \sec^{- 1} 2 + \sin^{- 1} \left( \frac{1}{2} \right) = 2 \sec^{- 1} \left( \sec\frac{\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{\pi}{6} \right)\]
\[ = 2 \times \frac{\pi}{3} + \frac{\pi}{6}\]
\[ = \frac{5\pi}{6}\]

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११९]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 57 | पृष्ठ ११९

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