Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: y = cos x + C : y′ + sin x = 0 - Mathematics

प्रश्न

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

y = cos x + C : y′ + sin x = 0

बेरीज

उत्तर

y = cos x + C

$\frac{d y}{d x}$ = - sin x

⇒ y’ + sin x = 0

As a result, the function y = cos x + C provides a solution to the above differential equation.

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General and Particular Solutions of a Differential Equation

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Q 3 Q 2 Q 4

पाठ 9: Differential Equations - Exercise 9.2 [पृष्ठ ३८५]

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एनसीईआरटी Mathematics [English] Class 12

पाठ 9 Differential Equations
Exercise 9.2 | Q 3 | पृष्ठ ३८५

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Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: y = cos x + C : y′ + sin x = 0 - Mathematics

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Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: y = cos x + C : y′ + sin x = 0 - Mathematics

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