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Question
If 28C2r : 24C2r − 4 = 225 : 11, find r.
Solution
We have, 28C2r : 24C2r − 4 = 225 : 11
\[ \Rightarrow \frac{28!}{2r! (28 - 2r)!} \times \frac{(2r - 4)! (28 - 2r)!}{24!} = \frac{225}{11}\]
\[ \Rightarrow \frac{28 \times 27 \times 26 \times 25}{2r (2r - 1) (2r - 2) (2r - 3)} = \frac{225}{11}\]
\[ \Rightarrow 2r (2r - 1) (2r - 2) (2r - 3) = \frac{28 \times 27 \times 26 \times 25 \times 11}{225}\]
\[ \Rightarrow 2r (2r - 1) (2r - 2) (2r - 3) = 28 \times 3 \times 26 \times 11\]
\[ \Rightarrow 2r (2r - 1) (2r - 2) (2r - 3) = 4 \times 7 \times 3 \times 13 \times 2 \times 11\]
\[ \Rightarrow 2r (2r - 1) (2r - 2) (2r - 3) = (2 \times 7) \times 13 \times (3 \times 4) \times 11\]
\[ \Rightarrow 2r (2r - 1) (2r - 2) (2r - 3) = 14 \times 13 \times 12 \times 11\]
\[ \Rightarrow 2r = 14\]
\[ \Rightarrow r = 7\]
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