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If ∆ABC ~ ∆QRP, ar(ABC)ar(PQR)=94, AB = 18 cm and BC = 15 cm, then PR is equal to ______ - Mathematics

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Question

If ∆ABC ~ ∆QRP, `(ar(ABC))/(ar(PQR)) = 9/4`, AB = 18 cm and BC = 15 cm, then PR is equal to ______.

Options

  • 10 cm

  • 12 cm

  • `20/3` cm

  • 8 cm

MCQ
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Solution

If ∆ABC ~ ∆QRP, `(ar(ABC))/(ar(PQR)) = 9/4`, AB = 18 cm and BC = 15 cm, then PR is equal to 10 cm.

Explanation:


Given, ∆ABC ~ ∆QRP,

AB = 18 cm

And BC = 15 cm

We know that, the ratio of the area of two similar triangles is equal to the ratio of square of their corresponding sides.

∴ `("ar(∆ABC)")/("ar(∆QRP)") = ("BC")^2/("RP")^2` 

But, `("ar(∆ABC)")/("ar(∆PQR)") = 9/4`  ...[Given]

⇒ `(15)^2/("RP")^2 = 9/4`  ...[∵ BC = 15 cm, given]

⇒ (RP)2 = `(225 xx 4)/9` = 100

∴ RP = 10 cm

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Chapter 6: Triangles - Exercise 6.1 [Page 62]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 6 Triangles
Exercise 6.1 | Q 11 | Page 62

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