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Question
If xy = yx, then find `dy/dx`
Solution
xy = yx
y log x = x log y
By differentiating on both sides,
`y * 1/x + log x dy/dx = x * 1/y dy/dx + log y`
`dy/dx(logx - x/y) = log y - y/x`
`dy/dx = (log y - y/x)/(log x - x/y)`
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