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Question
Prove that cot2θ × sec2θ = cot2θ + 1
Solution
L.H.S = cot2θ × sec2θ
= `(cos^2theta)/(sin^2theta) xx 1/(cos^2theta)`
= `1/(sin^2theta)`
= cosec2θ
= 1 + cot2θ ......[∵ 1 + cot2θ = cosec2θ]
= R.H.S
∴ cot2θ × sec2θ = cot2θ + 1
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