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प्रश्न
Evaluate the following:
`sec^-1(sec (13pi)/4)`
उत्तर
We know that
sec-1 (sec θ) = θ, [0, π/2) ∪ (π/2, π]
We have
`sec^-1(sec (13pi)/4)=sec^-1[sec(4pi-(3pi)/4)]`
`=sec^-1[sec((3pi)/4)]`
`=(3pi)/4`
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