मराठी

Wnte the Value of Cos ( Tan − 1 X + Cot − 1 X 3 ) , When X = − 1 √ 3 - Mathematics

Advertisements
Advertisements

प्रश्न

Wnte the value of\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right), \text{ when } x = - \frac{1}{\sqrt{3}}\]

उत्तर

\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right) = \cos\left( \frac{\pi}{6} \right) \left[ \because \tan^{- 1} x + \cot^{- 1} x = \frac{\pi}{2} \right]\]
\[ = \frac{\sqrt{3}}{2}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११९]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 55 | पृष्ठ ११९

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Solve the equation for x:sin1x+sin1(1x)=cos1x


If tan-1x+tan-1y=π/4,xy<1, then write the value of x+y+xy.


If `(sin^-1x)^2 + (sin^-1y)^2+(sin^-1z)^2=3/4pi^2,`  find the value of x2 + y2 + z2 


Find the domain of `f(x)=cos^-1x+cosx.`


`sin^-1(sin3)`


Evaluate the following:

`cos^-1(cos5)`


Evaluate the following:

`cos^-1(cos12)`


Evaluate the following:

`tan^-1(tan  (6pi)/7)`


Evaluate the following:

`tan^-1(tan  (7pi)/6)`


Evaluate the following:

`tan^-1(tan  (9pi)/4)`


Evaluate the following:

`tan^-1(tan1)`


Evaluate the following:

`cosec^-1(cosec  (11pi)/6)`


Write the following in the simplest form:

`cot^-1  a/sqrt(x^2-a^2),|  x  | > a`


Write the following in the simplest form:

`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`


Write the following in the simplest form:

`tan^-1{(sqrt(1+x^2)+1)/x},x !=0`


Write the following in the simplest form:

`sin^-1{(x+sqrt(1-x^2))/sqrt2},-1<x<1`


Evaluate:

`cot(tan^-1a+cot^-1a)`


`tan^-1x+2cot^-1x=(2x)/3`


Solve the following equation for x:

`tan^-1  2x+tan^-1  3x = npi+(3pi)/4`


Solve the following equation for x:

tan−1(x + 2) + tan−1(x − 2) = tan−1 `(8/79)`, x > 0


`sin^-1  63/65=sin^-1  5/13+cos^-1  3/5`


Solve the following:

`cos^-1x+sin^-1  x/2=π/6`


Solve `cos^-1sqrt3x+cos^-1x=pi/2`


Evaluate the following:

`tan  1/2(cos^-1  sqrt5/3)`


`tan^-1  1/7+2tan^-1  1/3=pi/4`


Show that `2tan^-1x+sin^-1  (2x)/(1+x^2)` is constant for x ≥ 1, find that constant.


Solve the following equation for x:

`cos^-1((x^2-1)/(x^2+1))+1/2tan^-1((2x)/(1-x^2))=(2x)/3`


Write the value of tan1x + tan−1 `(1/x)`for x > 0.


Write the value of sin (cot−1 x).


Evaluate sin

\[\left( \frac{1}{2} \cos^{- 1} \frac{4}{5} \right)\]


Wnte the value of the expression \[\tan\left( \frac{\sin^{- 1} x + \cos^{- 1} x}{2} \right), \text { when } x = \frac{\sqrt{3}}{2}\]


Find the value of \[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right)\]


sin\[\left[ \cot^{- 1} \left\{ \tan\left( \cos^{- 1} x \right) \right\} \right]\]  is equal to

 

 

The number of solutions of the equation \[\tan^{- 1} 2x + \tan^{- 1} 3x = \frac{\pi}{4}\] is

 


The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]


If tan−1 3 + tan−1 x = tan−1 8, then x =


The value of sin \[\left( \frac{1}{4} \sin^{- 1} \frac{\sqrt{63}}{8} \right)\] is

 


Write the value of \[\cos^{- 1} \left( - \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\] .


Find the value of x, if tan `[sec^(-1) (1/x) ] = sin ( tan^(-1) 2) , x > 0 `.


Find the simplified form of `cos^-1 (3/5 cosx + 4/5 sin x)`, where x ∈ `[(-3pi)/4, pi/4]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×