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प्रश्न
Integrate the functions:
`x/(9 - 4x^2)`
उत्तर
Let `I = int x/(9 - 4x^2)` dx
Put 9 - 4x2 = t
⇒ -8x dx = dt
∴ `I = -1/8 int dt/t`
`= -1/8 log |t| + C`
`= 1/8 log 1/ |t| + C`
`= 1/8 log 1/ (|9 - 4x^2|) +C`
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