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`(Cos^3 Theta +Sin^3 Theta)/(Cos Theta + Sin Theta) + (Cos ^3 Theta - Sin^3 Theta)/(Cos Theta - Sin Theta) = 2` - Mathematics

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Question

`(cos^3 theta +sin^3 theta)/(cos theta + sin theta) + (cos ^3 theta - sin^3 theta)/(cos theta - sin theta) = 2`

Solution

LHS= `(cos^3 theta +sin^3 theta)/(cos theta + sin theta) + (cos ^3 theta - sin^3 theta)/(cos theta - sin theta) `

       =` ((cos theta + sin theta)(cos^2 theta- cos theta sin theta + sin^2 theta))/((cos theta + sin theta)) + ((cos theta - sin theta )(cos^2 theta+ cos theta  sin theta + sin^2 theta))/((cos theta - sin theta))`

    =` (cos^2 theta + sin ^2 theta - cos theta sin theta ) + ( cos^2 theta + sin^2 theta + cos theta sin theta)`

    =`(1- cos theta sin theta) +( 1+ cos theta sin theta)`

    = 2
    = RHS
  Hence, LHS = RHS

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Chapter 8: Trigonometric Identities - Exercises 1

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RS Aggarwal Mathematics [English] Class 10
Chapter 8 Trigonometric Identities
Exercises 1 | Q 22
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