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Question
Find the area of the region lying in the first quandrant bounded by the curve y2= 4x, X axis and the lines x = 1, x = 4
Solution
Let A be the required area
Consider the equation, y2 = 4x
∴ 1y=2sqrtx`
∴ `A=int_1^4ydx`
`=int_1^4 2sqrtxdx`
`=2.2/3[x^(3/2)]_1^4`
`=4/3[(4)^(3/2)-(1)^(3/2)]`
`=4/3[8-1]`
`A=28/3` sq.units
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